Newspaper advertisement on front page
abc
89.4%
jkl
86.3%
pqr
80...
Mathematics, 11.09.2019 22:30 kellimcollier896
Newspaper advertisement on front page
abc
89.4%
jkl
86.3%
pqr
80.5%
tuv
88.7%
xyz
89.1%
total
82.4%
the probabilities of different newspapers having an advertisement on the front page are given in the table. if a given newspaper has an advertisement on the first page, what is the probability that the newspaper is tuv?
a.
82.4%
b.
86.3%
c.
88.7%
d.
insufficient data
Answers: 2
Mathematics, 21.06.2019 16:30, robclark128
You are updating your garage and the only thing left to paint is your garage day. you're only going to paint the slide that faces the street. the garage door is 9 fert 8inches tall and 120 inches wide. you need to know the surface area of the side of the garage door to determine how much paint to buy. the hardware store sells paint by how much covers a square foot. what is the surface area you should report to the hardware store what is the answer
Answers: 3
Mathematics, 21.06.2019 19:30, mary9590
Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.
Answers: 3
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