Find four consecutive integers whose sum is 114.

If n is the first of these integers, then the other three are n + 1, n + 2, and n + 3. Then

n + (n + 1) + (n + 2) + (n + 3) = 114

4n + 6 = 114

4n = 108

n = 27

So the four numbers are 27, 28, 29, and 30.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2