If a ball dropped from a tower reaches the ground after 3.5 seconds, what is the height of the tower? given: g = –9.8 meters/second2 a. 56.00 meters b. 60.03 meters c. 62.08 meters d. 62.50 meters

B. 60.03 meters.

Step-by-step explanation:

We use the equation of motion under gravity:

h = ut - 0.5gt^2      where h = height, t = time and u = initial velocity.

h = (0)(3.5) - 0.5 * -9.8 * 3.5^2

= 60.025 m.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

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