Suppose that iq scores have a bell-shaped distribution with a mean of 97 and a standard deviation of 12. using the empirical rule, what percentage of iq scores are greater than 133? do not round your answer.

0.15%

Step-by-step explanation:

We have been given that IQ scores have a bell-shaped distribution with a mean of 97 and a standard deviation of 12. We are asked to find the percentage of IQ scores that are greater than 133 using the empirical rule.

First of all, we will find z-score for given sample score of 133 as z-score tells us a data point is how many standard deviation away from mean.

, where,

= Z-score,

= Sample score,

= Mean,

= Standard deviation.

We know that according to the empirical rule 68% of data lies within one standard deviation of mean, 95% of data lies within two standard deviation of mean and 99.7% of data lies within one standard deviation of mean.

Since 133 is 3 standard deviation above mean, so 0.3% lies above and below 3 standard deviation.

Since we need IQ scores above 133, so we will divide 0.3% by 2 as:

Therefore, 0.15% of IQ scores are greater than 133.

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x