The sum of 3 consecutive odd integers is 7 less than 4 times the largest number. find all 3 #’s plz show work
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The integers are -3, -1 and +1.

Step-by-step explanation:

Let the first integer is X

=> the other two consecutive odd integers are X+2 and X+4

Now we have given that their sum is 7 less than 4 times the largest number

Thus the first integer is -3

the second is (-3+2) = -1

and the third integer is (-3+4) = +1

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If any confusion, please comment.

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81

a is the best answer choice