X= 1/4y^2 the focus of the parabola is: (0, 1) (1, 0) (0, -1)

x= 1/4y^2

Vertex form is written as x = a(y-k)^2 + h

Using the given equation determine the values for a, h and k:

a = 1/4 , k = 0, h = 0

The vertex of a parabola is (h,k) = (0,0)

Find the distance form the vertex to a focus using the formula 1/4a

from above we know a = 1/4 so now you have:

1/(4(1/4))

Simplify

1/(4(1/4)) = 1

p = 1

The focus is (h+p,k)

Using the values  you have:

Focus = (0+1, 0)

= (1,0)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

i am not sure :

step-by-step explanation: