The width of the rectangle is five feet less than the length. if the perimeter of the rectangle is 34 feet find both dimensions

length = 11 ft, width = 6 ft

Step-by-step explanation:

Let w be the width, l be the length and p the perimeter. You can write down the following equations:

1. w = l - 5

2. p = 2*(w + l)

Now you have two equations with two unknown.

Plugging eq.1 in eq.2:

p = 2*(l-5 + l)

p = 2*(2*l - 5)

p = 4*l - 10

Remember p = 34

34 = 4*l - 10

4*l = 44

l = 11

Using eq.1 to solve for w:

w = 11 - 5

w = 6

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