Find the equilibrium solutions of the ordinary differential equation
y' = x^2 cos^3 y
which of these solutions are stable?

=π/2 + nπ =(π/2)*(1+2n)    where n∈Z (integers)

if n=even, Y is stable

if n=odd, Y is unstable

Step-by-step explanation:

y' = x^2 cos^3 y

Equilibrium solutions occur when y'(y,x) =f(y,x)=0, we need to find y=Y=constant and satisfy this.

⇒ ⇒

=π/2 + nπ =(π/2)*(1+2n)    where n∈Z (integers)

Stability analisys, f(y,x)=

(i.) If f(y,x)) < 0 on the left of Y, and f(y) > 0 on the right of Y, then the equilibrium solution is unstable.

(ii.) If f(y,x) > 0 on the left of Y, and f(y) < 0 on the right of Y, then the equilibrium solution y = c is stable.

(iii.) If f(x) > 0 on both sides of X, or f(x) < 0 on both sides of c, then the equilibrium solution y = X is semi-stable.

So, In the graph annexed we see f(y,x)= , we can verify that:

if n=even, Y is stable

if n=odd, Y is unstable

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%

a

step-by-step explanation: