The class midpoint of a class is
a. all of the above
b. the largest value of that class minus the class width
c. the difference between the largest and smallest values of that class
d. the difference between the largest and smallest values of that class divided by 2
e. the center of that class, which is the sum of its largest and smallest values divided by 2
f. none of the above.

The center of that class, which is the sum of its largest and smallest values divided by 2 ⇒ E

Step-by-step explanation:

* Lets explain what is the class mid-point

- It is defined as the average of the upper and lower class limits

- The class midpoint is the lower class limit plus the upper class limit

 divided by 2

- The easiest way to find the class mid-point is to add the upper

  and lower boundary and divide your answer by two

- The lower limit for every class is the smallest value in that class.

- The upper limit for every class is the greatest value in that class

* Lets solve the problem

- It is not the largest value of that class minus the class width

- Its not the difference between the largest and smallest values of

 that class

- It is not the difference between the largest and smallest values of

that class divided by 2

- It is the center of that class, which is the sum of its largest and

 smallest values divided by 2

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40

step-by-step explanation:

divide, then simplify your answer.

1. make -15.66 ÷   5.8 a fraction. then divide.

2. simplify.  

3. final answer.