Imagine that a basketball is placed at the red free throw line (as shown above). the distance from the line to the edge of
the court is 4 meters. the height of the basket is 3 meters. if the ball were to move from the floor to the basket in a
straight line, how far would it travel? consider the following image to you.
width: 15 meters
length: 28.5 meters
height: 3 meters
a) 5m
b) 6m
c) 7m
d) 12m

  A)  5 m

Step-by-step explanation:

No ball is shown in the diagram. We assume that the distance of interest is the hypotenuse of a right triangle with legs 3 m and 4 m. Your knowledge of the 3-4-5 Pythagorean triple tells you the hypotenuse is 5 m.

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If you actually need to use the Pythagorean theorem equation, you are looking for "c" where a=4 and b=3:

  c² = a² + b²

  c² = 4² + 3² = 16 +9 = 25

  c = √25 = 5

The straight-line distance is 5 meters.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

thats one

step-by-step explanation: