Two taps can fill a tank in 30 minutes and 40 minutes. another tap can empty it in 24 minutes. if the tank is empty and all the three taps are kept open, in how much time the tank will be filled?

60 minutes.

Step-by-step explanation:

Find the time for filling the tank with the first 2 taps:

1/30 + 1/40 = 1/x

Multiply through by the LCD 120x:

4x + 3x = 120

x = 120 /7

= 17.14 minutes.

When the  other tap is emptying the tank we have

1/17.14 - 1/ 24 = 1/ x

0.05834 - .04167

= 0.01667

so x = 1 / 0.01667

= 60 minutes to the nearest minute.

answer: can and shows the work

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v