What is the midpoint of line segment a b ? a number line going from negative 9 to positive 9. a closed circle appears at negative 6 and is labeled a. a closed circle appears at negative 2 and is labeled f. a closed circle appears at positive 1 and is labeled g. a closed circle appears at positive 2 and is labeled h. a closed circle appears at positive 3 and is labeled l. a closed circle appears at positive 8 and is labeled b. point f point g point h point i

G is the mid-point of line segment AB ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- The mid-point of a line is the point which divides the line into

  two equal parts

- There are four points between points A and B

- The four points are F , G , H , L

- one of them is the mid-point of AB

- The location of A is -6

- The location of F is -2

- The location of G is 1

- The location of H is 2

- The location of L is 3

- The location of B is 8

* Lets find the distance between points A and B

∵ Point A is located at -6

∵ Point B is located at 8

∵ The distance between A and B = location of B - location of A

∴ AB = 8 - (-6) = 8 + 6 = 14 units

- The mid-point of AB will divide it into two equal part, the length

  of each part is 14/2 = 7 units

∴ The mid-point location will be after point A by 7 units

∵ The location of point A is -6

∴ The location of the mid-point = -6 + 7 = 1

∴ The location of the mid-point of AB is 1

∵ The location of point G is 1

∴ G is the mid-point of line segment AB

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

180°

step-by-step explanation:

sum of equilateral triangle=180°

< n=60°

< m=120°°[angle supplementary of equilateral angle]

< m+< r+< x=360°(sum of exterior angle of triangle)