What is the equation, in point-slope form, of the line that is
parallel to the given line and passes through the point (-3,
1)?
o y-1=-3(x+3)
y-1=-} (x + 3)
oy- 1=} (x + 3)
oy-1=3(x+3)

The equation in point slope form is y - 1 = 3/2 ( x+3)

Option D is correct.

Step-by-step explanation:

We need to find the equation in point slope form of the line parallel to the given line in graph and passes through the line (-3,1)

The general form of point slope is:

y - y₁ = m(x-x₁)

We need to find the slope of the given line.

The formula used is:

m = y₂ - y₁ / x₂ - x₁

The points of the line are (2,2) and (-2,-4)

m = -4 - 2/-2-2

m = -6/-4

m = 3/2

Since the lines are parallel so, there slopes will be same. So slope m = 3/2

Now, finding the point slope form having slope m=3/2 and point (-3,2):

y - 1 = 3/2 (x - (-3))

y - 1 = 3/2 ( x+3)

So, the equation in point slope form is y - 1 = 3/2 ( x+3)

Option D is correct.

○ y - 1 = 3⁄2(x + 3)

Step-by-step explanation:

According to the Point-Slope Formula, y - y₁ = m(x - x₁), all the negative symbols give the OPPOSITE term of what they really are, so be EXTREMELY careful inserting the coordinates into the formula with their CORRECT signs.

So, starting from the y-intercept of [0, -1], you do rise\run by either moving three units south over two units west, or three units north over two units east.

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

incomplete question. how do you expect anyone to you when you do not post the question in its entirety?