9^x= e^x+8
solve for x using logs

Step-by-step explanation:

I will make an assumption.

We are trying to solve:

We first need to have the same base on both sides.  So I'm going to write as using that natural log (ln( )) and e^() are inverses.

So we are going to rewrite the equation:

So now that the bases are the same we can set the exponents equal like so:

Using power rule we can bring down the x in front of ln( ):

Now we need to get our terms with x on one side and terms without x on the opposite side.  To do this, we just need to subtract x on both sides in this case:

Factor the left hand side like:

Now divide both sides by what x is being multiplied by:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco