What is the cost of constructing a fence 6 ft., 6 in. high around a lot measuring 90 feet by 175 feet, if the cost of erecting the fence is $1.25 per linear foot, and the cost of materials is $.825 per square foot of fence?

the cost of fencing comes out to be $ 3504.625

Step-by-step explanation:

to find the cost of construction of fence

dimension of fence 6 ft., 6 in. high  

dimension =   90 ft  × 175 ft

cost of erecting the fence is $1.25 per linear foot

cost of material = $.825 per square foot of fence

area of fencing = 2× ( 6.5 ft × 90 ft ) + 2 × (6.5 ft ×  175 ft)

                          = 3445 ft²

perimeter of fence = 2 × 90 + 2 × 175

                               =  530 ft

cost of fencing  = 3445 × 0.825  + 530 × 1.25

                          = $ 3504.625

hence, the cost of fencing comes out to be $ 3504.625

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°