On a coordinate plane, a curved line with a minimum value of (1, negative 4) crosses the x-axis at (negative 1, 0), and (3, 0), and crosses the y-axis at (0, negative 3). which lists all of the y-intercepts of the graphed function? (0, –3) (–1, 0) and (3, 0) (0, –1) and (0, 3) (–1, 0), (3, 0), and (0, –3)

D. (0,-3)

Step-by-step explanation:

Here use the vertex  and one point on the curve to determine the function

The vertex form equation is written as;

y=a(x-h)²+k  where h,k are coordinates of the vertex

First step is to substitute the coordinates of the vertex into the vertex form equation

y=a(x-h)²+k   where (h,k) = (1,-4)

y=a(x-1)²- 4  --------------------------(a)

Substitute coordinates for a point into the equation (a)

Using point (3,0)

y=a(x-1)²-4

0=a(3-1)²-4

0=a(2)²-4

0=4a-4-----------take -4 to the other side

4=4a-------------------divide by 4 both sides

a=1

Rewrite equation as

y=1(x-1)²-4

y=(x-1)²-4

y=x(x-1)-1(x-1)-4

y=x²-x-x+1-4

y=x²-2x-3

Graph the equation to view the y-intercepts

You notice the graph has y-intercept at (0,-3)

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2