If a committee of 3 people is to be selected from among 5 married couples so that the committee does not include a married couple, how many such committee are possible. a) 20 b) 40 c) 50 d) 80 e) 120

option D.

Step-by-step explanation:

given,

5 married couples and we have to form the committee of 3 people such that no married couple comes together in the committee.

total number of people present  = 5 × 2 = 10 people

selecting 3 people randomly = ¹⁰C₃  = 120 ways

number of ways of selecting couple = ¹⁰C₁× ⁴C₁

                                                             = 40 ways

so, ways to select committee which does not include married couple =

                                                              = 120 - 40 = 80 ways

so, the correct answer is option D.

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743