Suppose you just received a shipment of seven televisions. four of the televisions are defective. if two televisions are randomly selected, compute the probability that both televisions work. what is the probability at least one of the two televisions does not work?

The probability that hat both televisions work= 0.1837

The probability at least one of the two televisions does not work=0.8163

Step-by-step explanation:

Given : Total televisions = 7

Defective televisions = 4

The proportion of defective sets :  

Number of televisions selected = 2

Using binomial probability formula :

The probability that hat both televisions work. :_

The probability at least one of the two televisions does not work:-

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

it is 28 degrees colder in detroit than philadelphia.

step-by-step explanation:

what number adds to 21

-7 + ? = 21

-7 + 28 = 21

hope it