State the domain and range of the following relation by clicking on the answer to make the given answer correct.
{(x, y): y = x + 1, x is some even integer}
domain {x: x > = r}.
{x: x< =r}.
{x: x=r}.
{x: x (is not equal, sign) r}.
{x: x (belongs to r, sign) r}.
range: {y: y = r}.
{y: y (is not equal, sign) r}.
{y: y> =r}.
{y: y< =r}.
{y: y (belongs to r, sign) r}.
which ones are correct?
!
you so much in advance! : )

17

step-by-step explanation:

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}

the answer is:

the lateral area is equal to

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

have a nice day!