The floor of conference hall is made in a shape of ellipse. if the largest
chord has length 20 meters and the smallest is 16m what is the length
between the foci?
a. 24m b. 12m c .9root2 m d. 6m

b

Step-by-step explanation:

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B.  12 m.

Step-by-step explanation:

The focal length f is related to the semi minor axis (b)  and the semi major axis (a) as follows: f^2 = a^2 - b^2.

Here we have  a = 1/2* 20 = 10 and b = 1/2 * 16 = 8.

f^2 =  10^2 - 8^2 = 36

so f = 6.

So the length between the focii is 2*6 = 12m.

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

the answer is two. hope this !