Write the equation of the line that passes through (3, −2) and has a slope of 4 in point-slope form. (2 points)
a
y + 2 = 4(x − 3)
b
y − 3 = 4(x + 2)
c
x − 3 = 4(y + 2)
d
x + 2 = 4(y − 3)

A. y+2=4(x-3)

Step-by-step explanation:

To write an equation in slope-point form you write as;

y-y₁=m(x-x₁) where m is slope of line and (x₁,y₁) is one point on the line

In this question you are given m=4 and (x₁,y₁) as (3,-2) then the equation is

y-y₁=m(x-x₁)substitute values

y--2=4(x-3)simplify further

y+2=4(x-3)

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

i believe the answer is c.