using a directrix of y = −3 and a focus of (2, 1), what quadratic function is created?

Step-by-step explanation:

The distance between the focus and the directrix is the vertical distance from the point to the line:

  1 -(-3) = 4

The vertex is half that distance between the point and the line, so is at x=2 and ...

  y = (-3 +1)/2 = -1

The vertical scale factor of the quadratic is 1/(4p) where p is the distance from vertex to focus. Here, that distance is 2, so the equation in vertex form is ...

  y = (1/(4·2))(x -2)² -1

  y = (1/8)(x -2)² -1

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Check

Any point on the parabola is equidistant from the focus and directrix. This is easily checked at the vertex, which is halfway between focus and directrix, and at the points having the same y-value as the focus. Those two points are (-2, 1) and (6, 1), both of which are 4 units from the focus and 4 units from the directrix.

parallel and congruent

step-by-step explanation:

the movement of translation is linear.   these have the same translation because you are using the same rule for each point of the triangle so you will see the same slope being used to get from a point on the triangle to its image.

same slope!   you should think parallel when you see those 2 word together (well unless it's the same line but it can't be because we are coming from different points here)

congruent! because each point is being moved the same distance.