Latanya leaves her house at 12: 30pm and bikes at 12 mi/h to marta’s house she stays at marta’s house for 90mij both girls walk back to latanya’s house at 2.3mi/h . they arrive at latanya house at 3: 30pm how far is marat’s house from latanya house

2.9 mi

Step-by-step explanation:

The time difference t between 12.30pm and 3.30pm is 3h.

Let the distance to Marat's house be s.

The equation to calculate velocity v is given by:

v = distance / time.

Now you can write an equation for the time difference t and use the two velocities and the 90 min(= 1.5h) she stays:

3 = s/12 + 1.5 + s/2.3

Solve this equation for s:

(1/12 + 10/23)* s = 1.5

s = 2.9

Martha's house is at a distance of 2.895 miles from LA Tanya's house.

Let the distance between Martha and LA Tanya's house = d

Total time = (3:30 - 12:30)pm = 3 hours

Stay time = 90 minutes = 1.5 hours

Recall :

Time = distance / speed

Therefore,

Cycling time = d / 12

Walking time = d / 2.3

Total time could be defined as :

Cycling time + walking time + stay time

d/12 + d/2.3 + 1.5 = 3

d/12 + d/2.3 = 3 - 1.5

d/12 + d/2.3 = 1.5

Multiply the denominator by 10

d/120 + d/23 = 1.5/10

L.C.M of 120 and 23 = 2760

(23d + 120d) / 2760 = 1.5/10

143d/2760 = 1.5/10

Cross multiply

1430d = 4140

d = 4140 / 1430

d = 2.895 miles

Hence, the distance between Martha and LA Tanya's house is 2.895 miles.

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i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

step-by-step explanation:

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