Abusiness has $15,000 to spend on airline tickets to travel to a conference. it wants 27 of its employees to attend. the business wants to buy as many business-class seats as possible. the business-class seats cost $700. the economy-class seats cost $375. create a system of equations that models how many of each type of ticket the business should purchase.

15 business classes and 12 economy classes

Step-by-step explanation:

For this equation let x be the number of the amount of business classes and y be the amount of economy classes:

We are looking for 27 employees to attend the conference so:

x + 7 = 27

Then look for the amount of business classes and economy classes by how much is each seat so:

700x + 357y = 15,000 (The max limit)

Multiply the first equation by 700

700 * x  +  700 * y  =  700 * 27

700x + 700y = 18,900

Lets look for y by subtracting the second equation by the first equation:

700x + 357y = 15,000  -  700x + 700y = 18,900

700x - 700x = 0

0

357y - 700y = -325y

0   325y

Then 15,000 - 18,900 = -3,900

Meaning:

0  -325y = -3,900

To find y, we must divide -3,900 by -325y

-3900/-325 =

So y = 12

Then for x:

x + y = 27

Since y = 12

x + 12 = 27

Backwards formation:

27 - 12 = 15

x = 15

So there are 15 business classes and 12 economy classes

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )