Mathematics, 29.08.2019 18:30 sbailey0962

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals startfraction one-fourth endfraction left-parenthesis x minus 12 right-parenthesis.(x – 12). what is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

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The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 =...