Draw a diagram in which f is between a and e, f is also between r and s, and a, e, r, and s are noncollinear

See explanation

Step-by-step explanation:

1. Draw the segment AE and plot on this segment point F (F lies between A and E).

2. Draw a segment passing through the point F, which intersects segment AE. On this segment neme the endpoints R and S. Thus, point F lies between points R and S.

Remind that points are collinear, if they lie on the same line. Otherwise, these points are not collinear.

According to described construction, points A, E, R and S do not lie on the same line, these points are noncollinear (see attached diagram for details).

< 6 cm to > 26 cm i believe

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.