The length of the picture fram is 3in. greater than the width. the perimeter is less than 52in. describe the dimensions of the frame

length = 14.5 in

Width = 11.50 in

Step-by-step explanation:

Let the length of the picture = x

width be = y

Perimeter P=52

P is given as

P=2(x+y)

56=2(x+y)

x+y=28 (Dividing both sides by 2)   ---(A)

Also given that

the length of the picture fram is 3 in greater than the width.

x-y=3   (B)

Adding A and B

2x=29

dividing both sides by 2 we get

x=14.5

Putting this in B we get

14.5-y=3y=11.5

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b