Mathematics, 27.08.2019 22:30 briannagiddens

Im on my last try!
solve using the zero product property:
(x + 3)(x - 5) = 0
x = 3 or x = -5
x = -3 or x = 5
x = 3 or x = 5
x = -3 or x = -5
solve by factoring and applying the zero product property:
latex: x^2-11x\: +28=0 x 2 − 11 x + 28 = 0
x = - 4 or x = - 7
x = - 4 or x = 7
x = 2 or x = 14
x = 4 or x = 7
for what values of x is the equation true? (form 1st! )
latex: \: x^2-5x=36 x 2 − 5 x = 36
4 and -9
- 4 and - 9
- 4 and 9
4 and 9
for what values is the following true? (form 1st! )
latex: x^2+2x-4=20 x 2 + 2 x − 4 = 20
x = 4 or x = - 6
x = - 4 or x = 6
x = 2 or x = 4
x = - 2 or x = - 4
to find the solution to the equation using factoring, we need to first write it in standard form. which of the following choices is equivalent to the equation:
(x −2)(x + 5) = 18
latex: x^2+3x-28=0 x 2 + 3 x − 28 = 0
latex: x^2-3x-28=0 x 2 − 3 x − 28 = 0
latex: x^2+3x+8=0 x 2 + 3 x + 8 = 0
x^2+3x+28=0

Answers: 2

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You know the right answer?

Im on my last try!
solve using the zero product property:
(x + 3)(x - 5) = 0
x =...