Of all sixth graders, 70% sent a text
message yesterday. ten trials of a
simulation are conducted and the
data are recorded below.
62072, 34570, 80983, 04292, 83150,
36330, 96268, 14077, 77985, 13511
the numbers 0 through 6 represent
students who sent a text yesterday,
and the numbers 7 through 9
represent students who did not send
a text yesterday.
based on the simulated data, what
is the probability that 3 or more
of a group of 5 students randomly
selected will send a text today?
explain.

7. 153.86 ft

8. 12.56 ft

9. 78.5 m

10. 379.94 in

11. 132.665 m

12. 12.56 yd

13. 226.865 ft

14. 113.04 ft

15. 63.585 ft

16. 254.34 m

17. 50.24 cm

step-by-step explanation:

7.

8.

9.

10.

11.

12.

13.

14.

15.

16.

17.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value