Question it takes you 15 minutes to drive 6.0 miles in a straight line to the local hospital. it takes 10 minutes to go the last 3.0 miles, 2.0 minutes to go the last mile, and only 30 seconds (= 0.50 minutes) to go the last 0.50 miles. what is your average velocity for the trip? take the positive x x direction to be from your starting point toward the hospital.

average velocity comes out to be 24 mile/hr

Step-by-step explanation:

given,

15 minutes to drive 6.0 miles in a straight line

10 minutes to go the last 3.0 miles

2.0 minutes to go the last mile

30 seconds to go the last 0.50 miles

average velocity = total displacement/ total time

displacement is the shortest distance hence total displacement = 6 miles

total time = 15 min  = 15/60 = 0.25 hrs

average velocity =

                             = 24 mile/hr

hence, average velocity comes out to be 24 mile/hr

find the magnitude of the trig term  

csc

(

x

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−

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by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

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the range is  

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or  

y

≥

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(

−

∞

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∪

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{

y

|

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step-by-step explanation:

step-by-step explanation: