Consider the tangent line to the curve y = 6 sin(x) at the point (π/6, 3). (a) find a unit vector that is parallel to the tangent line to the curve at the given point.

Step-by-step explanation:

We have given the equation y = 6 sin (x)

On differentiating both side

As it passes through the point

So

Now the unit vector is parallel to the tangent so m will be 5.196

This passes through the point

So unit vector will be

6(h+1)/2=a

a=area

step-by-step explanation:

its the same thing as a square or rectangle but after multiplying two sides you need to divide it by two.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube