An urn contains 1 green ball, 1 red ball, 1 yellow, and 1 white ball. idraw 4 balls with replacement. what is the probability that there is at least onecolor that is repeated at least twice?

The probability is : 0.90625

Step-by-step explanation:

4 balls are drawn with replacement.

There are total 4 balls so, total ways will be = = 256

Now, a green ball can be selected in 4C1 ways that is = 4 ways

Red ball can be selected in 3C1 ways = 3 ways

Yellow ball can be selected in 2C1 ways = 2 ways

And white ball can be selected in 1C1 way = 1 way

Now P(at least one color twice) = 1-P(no color repeat twice)

So, P(no color repeat twice) =

=

P(at least one color twice) =

Hence, the probability is 0.90625.

the answer is b

12r - 8 - 12

you have to combine like terms. below i have bolded the like terms:

12r - 8 - 12

together it combines to:

12r - 20

hope this !