Suppose for a function y = f(x) that f(-2) = 3 and f'(-2) = 23 . write the equation of the tangent line to f(x) at x = -2.

The equation of tangent line is .

Step-by-step explanation:

Given information: y = f(x) that f(-2) = 3 and f'(-2) = 23 .

The given function is

Differentiate with respect to x.

We need to find the equation of the tangent line to f(x) at x = -2.

Slope of tangent line is

Slope of line is 23.

At x=-2 the value of function is 3. It means the tangent line passes through the point (-2,3).

Equation of tangent line is

Add 3 on both sides.

Therefore the equation of tangent line is .

what is the starting amount? the question is not clear sorry.

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x