If a cow costs 1$ a sheep costs 0.5$ and a horse cost 10$ and you have 100$ to buy 100 animals and you have to have one of each. how many of each did you buy?

5 cows of 5$, 90 sheep of 45$ and 5 horses of 50$.

Step-by-step explanation:

Cost of 1 cow = $1

Cost of 1 sheep = $0,5

Cost of 1 horse = $10

Let number of cows be x and , number sheep be y and number of horses be z.

...(1)

..(2)

Since , there should be minimum 1 animal. we will be using hit and trial method for the solution:

1) Put value of x =1 ,  in (1) and (2),we get two equation in two variables:

Solving above equation we get , y =93.79 , z= 5.21 (Not possible)

2) Put value of x = 2 ,  in (1) and (2),we get two equation in two variables:

Solving above equation we get , y =92.85 , z= 5.15 (Not possible)

3)  Put value of x = 5 ,  in (1) and (2), we get two equation in two variables:

Solving above equation we get , y =90 , z= 5 (possible)

5 cows of 5$, 90 sheep of 45$ and 5 horses of 50$.

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.