Through ( 3,2) parallel to y=5/2x-5 . what is the slope intercept form of the equation

y=(5/2)x+(-11/2)

Problem: What is the slope-intercept form for a line going through (3,2) and is parallel to y=(5/2)x-5?

Step-by-step explanation:

Parallel lines have the same slope.

The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept. So we see that m=5/2 since that is the slope of y=5/2 x-5.

y=(5/2)x+b

We know (x,y)=(3,2) is a point on the line so replacing x with 3 and y with 2 gives:

2=(5/2)(3)+b

2=(15/2)+b

Subtract 15/2 on both sides:

2-(15/2)=b

Simplify:

(4-15)/2=b

(-11/2)=b

So the equation is:

y=(5/2)x+(-11/2)

Step-by-step explanation:

The equation of a line has the following form:

Where m is the slope of the line and b is the intercept with the y axis.

If two lines of slopes m and n are parallel  then it is true that:

For the line the slope is:

So the slope of the parallel line is:

So the equation is:

To find b we substitute the point (3, 2) in the equation and solve for b

Then the equation of the line in the form of pending interception is:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

pi x^2

step-by-step explanation:

pi times x squared