Find the equation of a line that contains the points (−5,2) and (4,6). write the equation in slope-intercept form.

y=(4/9)x+(38/9)

Step-by-step explanation:

let (-5,2)=(x1,y1)

(4,6)=(x2,y2)

now

using two point form

y-y1=((y2-y1)/(x2-x1))(x-x1)

or, y-2= ((6-2)/(4-(-5)))(x-(-5))

or,y-2 =4/9 (x+5)

or,9(y-2)=4(x+5)

or,9y-18=4x+20

or,9y= 4x+38

y= (4/9)x+38/9[y=mX+c]

where

m=4/9

c=38/9

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c. (3,2,6) is the answer.