In one town, 66% of adults have health insurance. what is the probability that 4 adults selected at random from the town all have health insurance? round to the nearest thousandth if necessary.

The probability that 4 adults selected at random from the town all have health insurance is 0.1897

Step-by-step explanation:

Consider the provided information.

It is given that 66% of adults have health insurance.

Let p = 66% = 0.66

Therefore q=1-0.66=0.34

We need to find the probability that 4 adults selected at random from the town all have health insurance.

Here the value of r is 4.

Substitute the respective values in the above formula.

Hence, the probability that 4 adults selected at random from the town all have health insurance is 0.1897

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.