In one town, 66% of adults have health insurance. what is the probability that 4 adults selected at random from the town all have health insurance? round to the nearest thousandth if necessary.

The probability that 4 adults selected at random from the town all have health insurance is 0.1897

Step-by-step explanation:

Consider the provided information.

It is given that 66% of adults have health insurance.

Let p = 66% = 0.66

Therefore q=1-0.66=0.34

We need to find the probability that 4 adults selected at random from the town all have health insurance.

Here the value of r is 4.

Substitute the respective values in the above formula.

Hence, the probability that 4 adults selected at random from the town all have health insurance is 0.1897

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: