What is the slope of any line parallel to the line 8x- 10y = 12 ?

The slope of any line parallel to the given line is 0.8

Step-by-step explanation:

we have the line

8x-10y=42

Isolate the variable y

Adds 10y both sides

8x-10y+10y=42+10y

8x=42+10y

Subtract 42 both sides

8x-42=10y

Divide by 10 both sides

y=0.8x-4.2

The slope m is equal to

m=0.8

Remember that

If two lines are parallel, then their slopes are the same

therefore

The slope of any line parallel to the given line is 0.8

sine

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)