If the area (in square units) of the region under the curve of the function f(x)=5 , on the interval from x=a to x=8 is 20 square units, what is the value of a?
answers: 4, 5, 6, 7, or 8?

8.

Step-by-step explanation:

In the question it says x=a then says x=8 if you do the common process of elimination you can concluded the a=8.

a = 4

Step-by-step explanation:

The function y = f(x) = 5 is simply a horizontal straight line

the interval x=a and x= 8 represent vertical straight lines that intersect x = a and x = 8.

Hence the area above the x-axis that is bound by f(x) on the top and x=a & x=8 on the sides is simply a rectangle with height = 5 and length = ( 8 - a ), and its area is given by

area = height x length = 5 (8-a)

we are given that the area = 20,

hence

area = 20 = 5(8-a)

(8-a) = 20/5

8-a = 4

-a = 4 - 8

-a = -4

a = 4

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

i belive those are the ones that are under 90 degreese.