Consider the following function. f(x) = x3/5, a = 1, n = 3, 0.7 ≤ x ≤ 1.3 (a) approximate f by a taylor polynomial with degree n at the number a. t3(x) = 3 5 (x−1)− 3 25 (x−1)2+ 7(x−1)3 125 +1 (b) use taylor's inequality to estimate the accuracy of the approximation f(x) ≈ tn(x) when x lies in the given interval. (round your answer to eight decimal places.) |r3(x)| ≤

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step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.