What is the radius of a circle whose equation is x2+y2−10x+6y+18=0?

The radius is 4 units

Step-by-step explanation:

We can find the radius of a circle through the following procedure:

Complete the square for x and y  

Put in the format for a circle. (x-h)² + (y-k)² = r², center at (h,k) with radius = r

x2+y2−10x+6y+18=0

Now subtract 18 from both sides.

x^2+y^2−10x+6y+18-18=0-18

x^2 - 10x + y^2 + 6y = -18

(x-5)^2 - 25 + (y+3)^2 - 9 = -18

(x-5)^2 + (y+3)^2 = -18+9+25

(x-5)^2 + (y+3)^2 = 16

So,

r^2 = 16

Take square root at both sides:

√r^2 = √16

r = 4

Thus the radius is 4 units

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

1e+27

step-by-step explanation: