Anew youth sports center is being built in pagosa springs. the permitted of the rectangular playing field is 524 yards. the length of the field is 8 yards lass then quadruple the with. what are the dimensions of the playing field?

Length = 208 yards

Width = 54 yards

Step-by-step explanation:

Let the length of the field be "x" yards and the width be "y" yards. Its given that the length is 8 less than quadruple(4 times) the width. So x is 8 less than 4y. We can write this in equation as:

x = 4y - 8                               Equation 1

Perimeter of the field is given to be 524 yards. Since, the field is rectangular, its perimeter is calculated as:

Perimeter = 2 (Length + Width)

Using the values, we get:

2(x + y) = 524                         Equation 2

Substituting the value of x from Equation 1 into Equation 2, we get:

2(4y - 8 + y) = 524

2(5y - 8) = 524

5y - 8 = 524/2

5y - 8 = 262

5y = 262 + 8

5y = 270

y = 54 yards

Substituting the value of y in Equation 1, we get:

x = 4y - 8 = 4(54) - 8 = 208 yards

Thus, the length of the playing field is 208 yards and its width is 54 yards.

the answer is c

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!