Afootball quarterback goes for a two-point conversion when the ball is within 10 yards of the end zone. during the game, he has two opportunities for a two-point conversion. he misses the first attempt 50% of the time. when he misses the first attempt, he misses the second attempt 15% of the time. what is the probability of missing both two-point conversion attempts?

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Step-by-step explanation:

We look for the probability that the player fails the first attempt and also fails the second attempt.

We know that the probability that the quarterback fails the first attempt is:

We know that the probability that the quarterback fails the second attempt after failing the first is:

Then the probability of failure of both attempts is:

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.