![\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\implies cos(\theta)=\sqrt{1-sin^2(\theta)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(x)=cos(x)\implies sin(x)=\sqrt{1-sin^2(x)} \\[1.5em] [sin(x)]^2=\left[\sqrt{1-sin^2(x)}\right]^2\implies sin^2(x) = 1-sin^2(x)\implies 2sin^2(x)=1](/tpl/images/0186/3313/4bc3a.png)
Find all solutions of
sin(x) = cos(x)
in the interval [-π, π)...
Mathematics, 22.08.2019 00:30 daisa02
Find all solutions of
sin(x) = cos(x)
in the interval [-π, π)
Answers: 3
Other questions on the subject: Mathematics
Mathematics, 21.06.2019 18:30, nina288
Astuntman jumping off a 20-m-high building is modeled by the equation h=20-5t^2, where t is the same in seconds. a high-speed camera is ready to film him between 15m and 10m above the ground. for which interval of time should the camera film him?
Answers: 1
Mathematics, 21.06.2019 21:00, taylordalton93
Factor the trinomial below. 12x^2 - 32x - 12 a. 4(3x+3)(x-1) b. 4(3x+1)(x-3) c. 4(3x+6)(x-2) d. 4(3x+2)(x-6)
Answers: 2
You know the right answer?
Questions in other subjects:
Mathematics, 01.03.2021 17:40
Mathematics, 01.03.2021 17:40
English, 01.03.2021 17:40
Mathematics, 01.03.2021 17:40
