The vertices of ∆abc are a(-2, 2), b(6, 2), and c(0, 8). the perimeter of ∆abc is units, and its area is square units.

Perimeter : 22.81 to the nearest hundredths

Area: 24 square units

Step-by-step explanation:

The vertices of ∆ABC are located at A(-2, 2), B(6, 2), and C(0, 8).

The perimeter is the distance around the figure.

Use the distance formula to find the side lengths of the triangle and add them up.

The distance formula is

units

units

units

The perimeter is 8+6.32+8.49=22.81 units

The area of this triangle is given by: (see attachment)

square units.

man its nopq i just guessed and got it right so uhh

g00d lucc

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15