Which of the following steps were applied to abc obtain a'b'c' ?

A is located at (2,5)

A' is located at (5,7)

Subtract the X's and then the Y's to get how much it moved:

5-2 = 3 unit shift to the right.

7-5 = 2 unit shift up.

The answer would be A.

Shifted 3 units right and 2 units up.

Step-by-step explanation:

Given  : Graph.

To find : Which of the following steps were applied to ABC obtain A'B'C'.

Solution : We have given  Graph.

Original Triangle = ABC

Translated Triangle = A'B'C'.

Coordinate

A (2, 5)→→→A '(5, 7)

B( 3 ,10)→→→B'(6 ,12)

C( 7 ,5)→→→C'( 10 ,7)

We can see x coordinate increased by 3 and y coordinates increased by 2.

A (2+3, 5+2)→→→A '(5, 7)

B( 3+3 ,10+2)→→→B'(6 ,12)

C( 7+3 ,5+2)→→→C'( 10 ,7)

Therefore, Shifted 3 units right and 2 units up.

answer: slight chance that it will happen

step-by-step explanation:

0.6

39mph

step-by-step explanation: