Jeannie's scores on her first four tests were 80, 65, 87, and 75. what will
she have to score on her next test to obtain an average of at least 80 for the term?

She will have to score 93.
(80+65+87+75+x)/5 = 80
307+x = 400
x =400-307=93
Another way, easier to do in your head:
Notice that 65 is 15 below 80, 87 is 7 above 80, and 75 is 5 below 80. The overall situation is 13 below 80 (because -15+7-5=-13). For a number to push the average back to 80, it must be 13 higher than 80. 80+13=93

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

What is the question that you needed answered?