Can 11 12 13 14 and 17 be done by the time i'm done with my shower , liking following 4 starting and marking branliest to any1 who can hell plz

11.) 2x+b

12.) 2(x+y) or 2x+2y

13.) 4(a-b) or 4a-4b

14.) 4a-b

17.) 5 b^{2}c^{3}[/tex]

Step-by-step explanation:

11.) twice x means 2x. So we can now substitute "twice x" with 2x to help the question be less confusing. Our question is now: "The sum of 2x and b". Sum means this is addition, so the answer is 2x+b

12.) "Twice the sum of x and y". This is meant to trick you but it means "The sum of x and y two times." This can be written as 2(x+y). If you want to distribute it to it's simplest terms the answer can be written as 2x + 2y

13.) "4 times the difference of a and b". Same as question 12. The question is asking for the value of the difference of a and b, which is a-b, four times. We can write this as 4(a-b). If you want to simplify it, the answer can be written as 4a-4b

14.) "The difference of 4 times a and b". The "and" in the sentence tells us that it does not want the 4 times of b too. It's separated, meaning the equation should be written as 4a - b

17.) 5 x b x b x c x c x c. First we combine like terms. We have three different terms in this equation. 5, b, and c. There are two b's, so . There are three c's, so . Now that we've combined like terms, we can rewrite our equation as:

47 - 90 = 43

43 - 180 = x

x = 137

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: