Find the domain of

You cannot have a square of a negative so you have to see what values of x would not produce a negotiate inside the square root.

Set y=0
And square both side to cancel the sqrt
3x-8=0
And solve for x
X=8/3

So therefore x>= 8/3
And the domain is { x E R >= 8/3 }

Btw E is meant to be the epsilon