How many different three-digit numbers can be written using digits from the set 5, 6, 7, 8, 9 without any repeating digits?

60 different numbers can be formed

Step-by-step explanation:

Note that we have 5 different digits, and we must select 3 of them. They should not be repeated

The order of selection is important in this case, because the number 532 is not the same as the number 235.

So we have a permutations problem, where we have a set of n elements and we want to choose r from them.

Then we define the permutacion as:

In this case note that n=5 because there are 5 elements in the set.

r = 3 because we combine the elements to form three-digit numbers

Then:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

gmt is 4 hrs ahead of edt so just add four hours to 1: 14: 20 (minutes and seconds stay the same)

gmt is 5: 14: 20

hope this !

~just a girl in love with shawn mendes